x^2+6x-2880=0

Solution for x^2+6x-2880=0 equation:

x^2+6x-2880=0

a = 1; b = 6; c = -2880;
Δ = b2-4ac
Δ = 62-4·1·(-2880)
Δ = 11556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11556}=\sqrt{36*321}=\sqrt{36}*\sqrt{321}=6\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{321}}{2*1}=\frac{-6-6\sqrt{321}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{321}}{2*1}=\frac{-6+6\sqrt{321}}{2}
$